Basic Principles and Calculations in Chemical Engineering (8th Edition) (2012) by David M. Himmelblau

Author:David M. Himmelblau [Himmelblau, David M.]
Language: por
Format: epub
Publisher: Prentice Hall
Published: 0101-01-01T00:00:00+00:00

Moles of O2 in with air including excess:

(1 + 0.04)(0.5 mol O2) = 0.52 mol O2

Therefore, 0.52/0.21 = 2.48 mol air enters containing 1.96 mol nN2.

Specifications: 65% of the carbon burns to CO: (0.65)(2) = 1.30.

Basis: 1 mol of H2C2O4 enters

Element material balances:

The results:

nH2O = 1.0; nCO2 = 0.7; nCO = 1.3; nO2 = 1.82; nN2 = 1.96; total mol = 6.78

yH2O = 1 mol H2O/6.78 mol = 0.147

The partial pressure of the water in the product gas (at an assumed atmospheric pressure) determines the dew point of the stack gas; that is, the temperature of saturated steam that equals the partial pressure of the water is equal to the dew point of the product gas:

Download

Copyright Disclaimer:
This site does not store any files on its server. We only index and link to content provided by other sites. Please contact the content providers to delete copyright contents if any and email us, we'll remove relevant links or contents immediately.