Mathematical Olympiad Treasures by Titu Andreescu & Bogdan Enescu
Author:Titu Andreescu & Bogdan Enescu
Language: eng
Format: epub
Publisher: Birkhäuser Boston, Boston, MA
in which there are m+(nâ1)=kâ1 terms. For this, we have to check that the sum sâ²=y 2+y 3+â¯+y n verifies the condition sâ²<m(nâ1). Because y 1â¥y 2â¥â¯â¥y n , it follows that , so that
as needed.
Problem 1.87
The sequence (x n ) nâ¥1 is defined by x 1=1, x 2n =1+x n and for all nâ¥1. Prove that for any positive rational number r there exists an unique n such that r=x n .
Solution
Note that all the terms of the sequence are positive numbers and that x 2n >1, x 2n+1<1 for all nâ¥1. We prove by induction on kâ¥2 the following statement: for all positive integers a,b such that and a+bâ¤k, there exists a term of the sequence equal to . If k=2, then a=b=1 and . Suppose that the statement is true for some k>2, and let a,b be coprime positive integers such that a+b=k+1. If a>b, then we apply the induction hypothesis to the numbers aâb and b. Clearly, and (aâb)+b=aâ¤k; therefore, there exists n such that . But then
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