Programming Rust by Unknown

Author:Unknown
Language: eng
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Since only s is pointing to the list, the list’s reference count is 1; and since the list is the only object pointing to the strings, each of their reference counts is also 1.

What happens when the program executes the assignments to t and u? Python implements assignment simply by making the destination point to the same object as the source, and incrementing the object’s reference count. So the final state of the program is something like this:

Python has copied the pointer from s into t and u, and updated the list’s reference count to 3. Assignment in Python is cheap, but because it creates a new reference to the object, we must maintain reference counts to know when we can free the value.

Now consider the analogous C++ code:

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