JavaScript in Plain Language - A Self-Study Method: JSON and AngularJS Prep by Tony de Araujo

Author:Tony de Araujo [de Araujo, Tony]
Language: eng
Format: epub
Published: 2014-09-26T22:00:00+00:00

13- Using splice(), insert "apple" in array mySort at position 1 (as a second item). Do not delete any existing item.

mySort should now contain ["banana", "apple", "chestnut"]

14- Using slice(), create a new array named newArray with a copy of the second and third items ( "apple" and "chestnut") from mySort array.

The newArray should now contain ["apple", "chestnut"].

(See my results on the next page.)

Answers to Lab work 9:

1- Take the following array y as an example and sort the array:

var y = ["grape", "apple", "banana"];

y.sort();

It returns ["apple", "banana", "grape"]

2- Assign a new array named mySort to the contents of a sorted array y:

var mySort = y.sort();

3- Test mySort:

mySort;

It returns ["apple", "banana", "grape"]

4- Now display the array mySort is a string type format,

and split the items whit 1 blank space. Hint: use join():

mySort.join(" ");

or you might have done this which is also correct:

console.log(mySort.join(" "));

It returns "apple banana grape" in a string format.

5- Now, instead of just displaying it, assign the items from mySort to a new variable z, but in a string format. Use a combination of space, forward slash, and space as a separator:

var z = mySort.join(" / ");

6- Call z:

z;

It returns "apple / banana / grape"

7- Use the indexOf() method to find the position of "banana" in array y:

y.indexOf("banana");

It returns 1, which means that "banana" exists and is located on position1 (second item).

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