Beyond the C++ Standard Library - An Introduction to Boost by By

Author:By
Language: eng
Format: epub
ISBN: 0321133544
Publisher: Addison Wesley Professional
Published: 2011-10-03T16:06:01.808867+00:00

If the class X does not support operator<<, the code does not compile. Unfortunately, it doesn't matter whether we are actually going to use operator<< or not, it just doesn't work. any_out always requires that the output operator be available.

any_out nope(X()); std::cout << nope; }

Convenient, don't you think? If a certain operation is available for all types that you plan to use in a certain context, adding those can be done in the same way we did to supply operator<< for our any_out class. It is not much harder to generalize the solution and parameterize on the operations, which makes this solution for extending the interface of any reusable.

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